by userbinator on 4/28/2025, 9:06:19 PM
by willis936 on 4/28/2025, 9:42:25 PM
If you need higher voltages at modest currents you can consider using one of many voltage doubler circuits after the booster. Just make sure you have enough Ic and simulate it.
by theamk on 4/29/2025, 3:32:50 AM
That's pretty bad... When calculating the efficiency, transitional effects and non-ideality of parts are critical. And what does the author choose? A generic mosfet, unnamed diode, constant duty cycle.. this is not realistic at all.
And the selection of parts seems just random, especially given low output power (0.1W), no design will use it. A MOSFET for 5V circuit. 1KHz switching frequency (!). Fixed duty cycle and voltage regulation via inductance changes (!!). Huge inductors (0.3H!), because of very low frequency.
All this blog post shows is that author can put parts into simulator. Very little relation to real world.
by Workaccount2 on 4/29/2025, 12:14:14 AM
If you get rid of the diode and instead use a well timed MOSFET, you can save a diode's drop worth of energy on each cycle. Synchronous switching supplies as they are called can have over 95% efficiency
by tfwnopmt on 4/27/2025, 1:14:40 PM
Have you considered this one? https://en.m.wikipedia.org/wiki/Cockcroft%E2%80%93Walton_gen...
by Calwestjobs on 4/28/2025, 9:49:55 PM
wehnelt interrupter / electrolytic interrupter can work as a switching up or down converter, fully analog, no transistors, thyristors, no ic, no capacitors, just coil.
single electric motor can be used stationary as a transformer
or in pairs, in motion like inverter, rectifier, (synchronous rotary converter)
autotransformer
That first circuit makes no sense. DC into a resistor and then a transformer won't do anything but create heat after the core saturates.